How would I make a program that prints out the odd positioned elements in an array of 10 integers.
C++ aRRay problem?
Its simple, see code below:
#include%26lt;iostream%26gt;
using namespace std;
int main()
{
int ar[10]; //populate the array yourself
int i = 1;
while(i%26lt;10)
{
cout%26lt;%26lt;ar[i]%26lt;%26lt;endl;
i = i+2;
}
return 0;
}
Hope this helps!
Reply:#include%26lt;iostream%26gt;
using namespace std;
int main()
{
int ar[10];
for(int i=0; i%26lt;10;i+=2)
cout %26lt;%26lt; ar[i] %26lt;%26lt; endl;
}
return 0;
}
Reply:int main()
{
int num[10];
for(int i=0; i%26lt;10;i++)
{
cin%26gt;%26gt; num[i] %26lt;%26lt; endl;
}
cout%26lt;%26lt;"Odd numbers in an array";
for(int a=0; a%26lt;10;a++)
{
if(num[a]%2==1)
{
cout%26lt;%26lt;num[a];
}
}
return 0;
}
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