How to create a 3D array in C language?

I want to put the following data into a array





ID Name Gender


FD4564 Mary F


IU4564 Peter M


ER4567 John M

How to create a 3D array in C language?
#include %26lt;stdio.h%26gt;





char array3d[][10][10] =


{


{"ID", "Name", "Gender"},


{"FD4564", "Mary", "F"},


{"IU4564", "Peter", "M"},


{"ER4567", "John", "M"}


};





int main()


{


for(int i=0; i%26lt;4; i++)


{


for(int j=0; j%26lt;3; j++)


{


printf("\t%s\t", array3d[i][j]);


}





printf("\n");


}





return 0;


}
Reply:Why not create a struct and populate an array with them?





struct Person


{


int id;


string name;


bool isMale;


}





Person *people = new Person[10];
Reply:I don't think you need a 3D array for this. Are you ever going to need to access something like this:





FD4564 Mary F


FD4564 Mary M


FD4564 Mary M





That doesn't make sense in this context. Use the struct and use char* str = new char[...] if you need variable length strings. Also if the dimensions of the array are going to change frequently, you need a different data structure (linked list).





If you really need to do it this way, then do this:





char* ** array = new char**[X];





for(i=0; i%26lt;X; i++)


{


array[i] = new char*[Y];


}





array[0][0] = "FD4564";


array[0][1] = "Mary";


array[0][2] = "F";





where X and Y are rows and columns, respectively.
Reply:Just initialize 3 different indices to point ID, Name, Gender respectively...





#include%26lt;stdio.h%26gt;


main()


{


int id, name, gender, arr[5][5][5] ;


....


....


for( id=0;id%26lt;cnt1;id++ )


{


for( name=0;name%26lt; cnt2; name++ )


{


for(gender=0;gender%26lt;cnt3;gender++ )


{


.....


..... // scan inputs from user ...


}}}


getch() ;


}
Reply:I would create a struct unless you have been explicitly told that you need to use a 3D array.

petal